A cell is connected between the points A and C of a circular conductor ABCD of centre 'O' with angle AOC = 60°, If B1 and B2 are the magnitudes of the magnetic fields at O due to the currents in ABC and ADC respectively, find the ratio of B1/B2 .

Hint: A magnetic field is a region of space near a magnet, electric current, or moving charged particle in which a magnetic force acts on any other magnet, electric current, or moving charged particle. magnetic intensity.The current flow is in the path of ABC and ADC, i' and i" respectively



Complete Step by Step Solution
According to the question A and C are connected to a cell
According to the picture
Angel AOC=60⁰
The i' current is flow throw the path of ABC and i" flow path is ADC
the ratio between i' and i" is
.....( The opposite angel of AOC=300)
......... equation (1)
So, total current flow
i = i'+i"......... equation (2)
i=5i"+i".........(value of i' is5i')
 ..... equation (3)
Put the value of i" in equation (1)

According to the formula of magnetic field
We know;. ....[a = area]
B'=k × i' [ k=]
B'= k×
Again,
B"= k×i"
B"=k×

The ratio of B' and B" is.....5

Note: An electric current is a flow of electric charge in a circuit. More specifically, the electric current is the rate of charge flow past a given point in an electric circuit. The charge can be negatively charged electrons or positive charge carriers including protons, positive ions or holes.always find the angles if the circuit is round.