A body moves with constant angular velocity on a circle. Magnitude of angular acceleration.
A. \[r{\omega ^2}\]
B. Constant
C. Zero
D. None of the above

Hint:The rate of change of angular velocity is called angular acceleration. When a body is moving in a circular path with constant speed than at every point the direction of linear velocity changes.

Formula used:
\[v = \omega r\]
where v is the linear velocity, \[\omega \] is the angular velocity and r is the distance of the point from the axis of rotation.
\[\alpha = \dfrac{{d\omega }}{{dt}}\]
Here \[\alpha \] is the angular acceleration of the particle and \[\dfrac{{d\omega }}{{dt}}\] is the rate of change of angular velocity.

Complete step by step solution:
When a body is moving in a circular path then the position of the body along the circular path changes with time. As we know, the rate of change of the linear position of the body with respect to time is called linear velocity. The rate of change of the angular position with respect to time is called the angular velocity.

It is given that the particle is moving in a circular path with constant angular velocity. Let at any time \[{t_1}\]the angular velocity is \[{\omega _1}\]. Then at any other time \[{t_2}\]the angular velocity is \[{\omega _2}\]. We need to find the angular acceleration of a particle on a circular path.

Image: Particle’s uniform circular motion

Let the angular acceleration of the body is \[\alpha \]. The distance of the body from the axis of rotation, i.e. from the center of the circular path is equal to the radius of the circular path. Using the formula for angular acceleration,
\[\alpha = \dfrac{{{\omega _2} - {\omega _1}}}{{{t_2} - {t_1}}}\]

As the angular velocity is constant \[{\omega _1} = {\omega _2}\]
\[\alpha = \dfrac{{\omega - \omega }}{{{t_2} - {t_1}}}\]
\[\Rightarrow \alpha = \dfrac{0}{{{t_2} - {t_1}}}\]
\[\therefore \alpha = 0\,rad/{s^2}\]
Hence, the angular acceleration of the body is equal to zero.

Therefore, the correct option is C.

Note: We should be careful while using the relation between the linear velocity and the angular velocity as it is for the instantaneous velocity. So, if we find the linear velocity of the accelerated body in a circular path then the obtained linear velocity will be corresponding to the angular velocity at that instant in time.